Re: [xml] xmlDocDumpFormatMemory

[Remy HAREL <rharel ext rd francetelecom com>]

Ok, I thought I had to allocate memory, it should be ok.

Thanks

_____________________________________________
Remy HAREL          -        Teamlog        |
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Linux registered user #224740               |
France Telecom Recherche & Developpement    |
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__________________@ http://www.chezrem.org @|




Jones, Mark A (Mark) wrote:

> below is an exerpt I yanked from the libxml2 documentation.  hope it helps - it suggests to me that the 
> function will return the size of the tree in the variable 'size'.
>
>
> Function:
> =========
> void    xmlDocDumpFormatMemory  (xmlDocPtr cur, xmlChar ** mem, int * size, int format)
>
> Description:
> ===========
> Dump an XML document in memory and return the #xmlChar * and it's size. It's up to the caller to free the 
> memory with xmlFree(). Note that @format = 1 provide node indenting only if xmlIndentTreeOutput = 1 or 
> xmlKeepBlanksDefault(0) was called
>
> cur: the document 
> mem: OUT: the memory pointer 
> size: OUT: the memory length 
> format: should formatting spaces been added 
>
>
> -----Original Message-----
> From: xml-bounces gnome org [mailto:xml-bounces gnome org]On Behalf Of
> Remy HAREL
> Sent: Friday, May 27, 2005 8:12 AM
> To: xml gnome org
> Subject: [xml] xmlDocDumpFormatMemory
>
>
> Re,
>
>  I'm using this function (xmlDocDumpFormatMemory ) to dump my xml tree 
> to a xmlChar*, I'm reading the documentation, and I am said it's up to 
> me to  specify &size ? how can I know the size of the three that will be 
> dumped ? I supposed the memory for the xmlChar** mem will be reserved by 
> the function itself ?
>
> I'm looking for this in the API Doc, but I can't find it.
>
> Regards,
>
> Remy
>
>