Re: [xml] how to add namespace-less node in python

[John Fleck <jfleck inkstain net>]

Try this:

#!/usr/bin/python -u
import libxml2

doc = libxml2.newDoc("1.0")
root = doc.newChild(None, "doc", None)
docns = root.newNs("http://www.krosing.net/testns","a";)
para = root.newChild(docns, "para", None)
title = doc.newDocNode(None, "title", None)
para.addChild(title)
print doc.serialize(None,1)


On Sat, 2003-12-20 at 09:50, Hannu Krosing wrote:
> Hallo
> 
> I need to add a node that has no namespace prefix while building xml doc
> in python (for my home-made SOAP server/client lib).
> 
> I know that such a tree is possible, as it is correctly generated by
> libxml2.parseFile :
> 
> >>> d = libxml2.parseFile('nstest.xml')
> >>> print d.serialize(None,1)
> <?xml version="1.0"?>
> <doc xmlns:a="http://www.krosing.net/testns";>
>   <a:para>
>     <title/>
>   </a:para>
> </doc>
> 
> 
> But I am unable to make similar tree programmatically:
>  
> >>> doc = libxml2.newDoc("1.0")
> >>> root = doc.newChild(None, "doc", None)
> >>> docns = root.newNs("http://www.krosing.net/testns","a";)
> >>> para = root.newChild(docns, "para", None)
> >>> title = para.newChild(None, "title", None)
> >>> print doc.serialize(None,1)
> <?xml version="1.0"?>
> <doc xmlns:a="http://www.krosing.net/testns";>
>   <a:para>
>     <a:title/>
>   </a:para>
> </doc>
> 
> I want to get <title/> and not <a:title/> .
> 
> What am I doing wrong ?
> 
> ----------------------
> Hannu
> 
> 
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