Re: how to display "busy" cursor ? and another question

[Allin Cottrell <cottrell wfu edu>]

On Sun, 5 Oct 2008, Han wrote:

> Thanks Allin. I tried your example code and it somehow did not work
> for me, i.e. the cursor does not show "watch".  

It can be tricky deciding which window(s) should display the watch 
cursor. See John Cupitt's suggestion.

> >    gdk_window_set_cursor(window, cursor);
> >    gdk_display_sync(display);
> >    gdk_cursor_unref(cursor);
> 
> [Han]  why do we call gdk_cursor_unref here ?

Otherwise (as I understand it) we'll leak memory, since a local 
reference to the newly created cursor will be retained (preventing 
its being freed), and the relevant pointer will fall out of scope 
when the enclosing function returns.

Allin Cottrell