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Re: Graph trendlines - a question.



Le jeudi 05 juillet 2007 �0:29 +0100, Gareth.J.Martin a �it :
> > Can you tell us what you saw and what you expected?
> 
> Plotting river stage data against discharge data and adding a power law 
> I obtained the equation:
> 
> ln(y) = 111.778ln(x)-445.855

this is the same as: y = exp(-445.855) * x^111.778

> I was expecting something of the form a=cB^d, which is the standard form 
> for stage-discharge relationships (I do have the exact relationship but 
> I am unable to get access to my work computer). I imagine it is my bad 
> maths but I'm just a bit confused! Thanks for the help.
> 
> Best wishes,
> Gareth.

-- 
Jean Br�rt <jean brefort normalesup org>




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