Re: [xslt] possible bug in xsltproc/libxslt

[Iosif Fettich <ifettich netsoft ro>]

Hi,

> > <xsl:sort select="/root/items/item[ item_id = @it_id]/@weight"
>                                     ^^^^^^^^^^^^^^^^^
>
>   1/ check with the latest version

will do

>   2/ use xsltproc -v to see what is happening

I did that, but the output regarding sort was minimal or I did overlook 
something, as I couldn't find anything relevant.

>   3/ there is no element with both attribute item_id and attribute
>      it_id in your input data. You're trying to sort on non-existent
>      data
>
> 3/ seems to indicate your XSLT code is bugged your select sort criteria is just
> wrong apparently.

hm... that might be the problem, indeed - but but but how to solve this 
then...?

<xsl:for-each select="/root/matches/match[ @cl_id = $class_id ]">
  <xsl:sort select="/root/items/item[ @item_id = @it_id ]/@weight"

Attribute @it_id should (in my hopes :) refer to the selected match 
element... what it apparently does not at all.

I tried to first set an variable that should hold the @it_id attribute and 
then use sort, like

<xsl:for-each select="/root/matches/match[ @cl_id = $class_id ]">
  <xsl:variable name="it_id" value="@it_id"/>
  <xsl:sort select="/root/items/item[ @item_id = $it_id ]/@weight"

but that's not working, as sort needs to be the first child of the 
for-each element.

I try to sort the _matches_ based on the weight of the _item_ elements 
they refer to.

Is there no way to refer to an attribute of the selected match element in 
the for-each  loop, so that the sort can use it to get the needed weight ?

Looks like I'm making something terribly wrong, but I'm really a bit lost 
here, sorry for the confusions.

Any pointer welcome.

Many thanks,

Iosif Fettich