Re: [xslt] date:time($some) strange result

[Charles Bozeman <cbozeman hiwaay net>]

When your timezone is set to GMT there is no timezone offset (+/-HH:MM)
therefore it is not displayed. The behavior you are seeing is correct. 
Did you find the problem stated in your original email?

Charlie B.

On Sat, 2004-10-16 at 06:41, Vladimir Grebenschikov wrote:
> В пт, 15/10/2004 в 14:17 -0500, cbozeman hiwaay net пишет:
> > The result you get is obviously wrong, however using libxslt-1.1.11 I get:
> > 17:51:07+04:00 which is correct. Maybe you need to upgrade.
> 
> 
> I have tried with libxslt-1.1.11.
> 
> I have found reason, it does not show +HH:MM for GMT TZ:
> This code:
> 
>   <xsl:template match="/">
>         .
>     <xsl:value-of select="date:time('2004-10-11T13:51:07+00:00')"/>;
>     <xsl:value-of select="date:time('2004-10-11T13:51:07+04:00')"/>;
>     <xsl:value-of select="date:time()"/>;
>   </xsl:template>
> 
> shows:
>         .
>     13:51:07;
>     13:51:07+04:00;
>     15:35:06+04:00;
> when I run it without TZ specify,
> 
> shows:
>         .
>     13:51:07;
>     13:51:07+04:00;
>     11:35:45;
> when TZ set to GMT:
> (env TZ=GMT xsltproc dt.xsl dt.xsl)
> 
> Not sure that it is completely right.
> 
> 
> > Charlie B.
> > 
> > Quoting Vladimir Grebenschikov <vova sw ru>:
> > 
> > > 
> > > Hi 
> > > 
> > > I try to use EXSLT date: xmlns:date="http://exslt.org/dates-and-times";
> > > 
> > > Is following result '13:51:07+04:00' is expected for
> > > date:time('2004-10-11T17:51:07+04:00') XPath expression ?
> > > 
> > > While date:time() returns time without zone-shift:
> > > '13:51:07'
> > > 
> > > -- 
> > > Vladimir B. Grebenschikov
> > > SWsoft Inc. vova sw-soft com
> > > _______________________________________________
> > > xslt mailing list, project page http://xmlsoft.org/XSLT/
> > > xslt gnome org
> > > http://mail.gnome.org/mailman/listinfo/xslt
> > >