Re: [xslt] name() = localname() ?

> I have a problem to get the namespace prefix of a node.
> name() and local-name() always give the same result but
> I want to get the node name with namespace prefix.

> Maybe somebody can help me how to do that.

I'm not positive but if the QName of an element without a prefix
declaration is the same as the localname.  Changing the source document to:
<test:test xmlns:test=""/>

should get the desired result, if that is acceptable.

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