Re: [xslt] xsl:param is not works..

[Matt Sergeant <matt sergeant org>]

On Thu, 7 Jun 2001, [ks_c_5601-1987] ±èÀº¿µ wrote:

> Hello,
> I can't English,, Sorry.. But, I try.... ^^
> I have a problem.. 
> when I use libxslt-0.9.0, xsl:param is works, using xsltproc --param tag value..
> But,, libxslt-0.10.0 and 0.11.0 is not works. 
> 
> xsl :
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
> <xsl:output method="text"/>
> 
> <xsl:param name="tag1"/>
> <xsl:param name="tag2"/>
> 
> <xsl:template match="/">
>    <xsl:if test="$tag1">
>       tag1: <xsl:value-of select="$tag1"/>
>    </xsl:if>
>    <xsl:text> and </xsl:text>
>    <xsl:if test="$tag2">
>    tag2 : <xsl:value-of select="$tag2"/>
>    <xsl:text> !! </xsl:text>
> </xsl:template>
> 
> </xsl:stylesheet>
> 
> xml:
> <doc/>
> 
> xsltproc --param tag1 test1 --param tag2 test2 test.xsl test.xml
> 
> result: and  !!

Strangely libxslt expects the params in what I call "XPath" syntax. So if
you pass in an unquoted word, it treats it as a path to resolve. Since you
have no tag called test1 in your source XML, it resolves to blank.

Pass it in as a string, as follows:

xsltprox --param tag1 "'test1'" --param tag2 "'test2'" test.xsl test.xml

(it's a pain in the ass, I know, but I hope they don't revert the change
because AxKit now has work-arounds for this!)

-- 
<Matt/>

    /||    ** Founder and CTO  **  **   http://axkit.com/     **
   //||    **  AxKit.com Ltd   **  ** XML Application Serving **
  // ||    ** http://axkit.org **  ** XSLT, XPathScript, XSP  **
 // \\| // ** mod_perl news and resources: http://take23.org  **
     \\//
     //\\
    //  \\