Re: forcing a a widget_queue_draw
- From: "Adrian E. Feiguin" <afeiguin uci edu>
- To: Ben Johnson <ben blarg net>
- Cc: gtk-list gnome org
- Subject: Re: forcing a a widget_queue_draw
- Date: Mon, 31 Jan 2005 17:16:51 -0800
The buttons are all toggle buttons. I am using
gtk_toggle_button_set_active to set the state of the button. When I
toggle one button, all the otthers should "untoggle", but they won't
look like that until I force the redraw. All the buttons are visible,
but the draw the wrong state: they don't appear toggled or untoggled
until I force the expose event with the mouse or another window.
I tried blocking the signal handler, it doesn't help.
Any ideas?
Thanks!
<ADRIAN>
Ben Johnson wrote:
Are all the widgets in this list the same type? What type are they?
Are they toggle buttons? (created with gtk_toggle_button_new() or
similar?) Or are they radio buttons? Or, if they are a new type defined
by you, what widget are they sub-classed from?
gtk_toggle_button_set_active(GTK_TOGGLE_BUTTON(buttons[n]), myboolean);
...should be all you need. in fact, it's possible that setting the
"button_down" and "active" properties directly is what's screwing things
up.
I assume you're calling gtk_widget_show() on these buttons before this
code is running. The buttons are visible, right?
Do you have "toggled" a signal handler connected to these buttons? In
that signal handler, do you activate or de-activate any buttons in the
array that did not receive the signal? If yes, you'll probably want to
block the signal before calling the .._set_active() function.
(I'm kind of grasping at straws if you can't tell. There are a lot of
possibilities.)
- Ben
On Mon, Jan 31, 2005 at 02:29:23PM -0800, Adrian E. Feiguin wrote:
Hi,
I probably wasn't clear. I just want to initialize my GUI. Suppose
that I have a list of buttons (something like radio buttons, although I
implement it myself in a customized fashion). I have a list of widgets,
if widget_list[n] == active_widget, then the button is down, else it's
up. So I do something like this:
...
if(widget_list[n] == active_widget){
GTK_BUTTON(buttons[n])->button_down = TRUE;
GTK_TOGGLE_BUTTON(buttons[n])->active = TRUE;
gtk_toggle_button_set_active(GTK_TOGGLE_BUTTON(buttons[n]),
TRUE);
}else{
GTK_BUTTON(buttons[n])->button_down = FALSE;
GTK_TOGGLE_BUTTON(buttons[n])->active = FALSE;
gtk_toggle_button_set_active(GTK_TOGGLE_BUTTON(buttons[n]),
FALSE);
}
gtk_widget_queue_draw(buttons[n]);
n++;
...
And its simply doesn't work as intended. The button does not appear down
until I force the expose event. With gtk-1 I would use gtk_widget_draw
instead of queue draw, and it worked just fine. But now in gtk-2 there
is no gtk_widget_draw. How do I force the widget to draw?
Thanks!
<ADRIAN>
Tristan Van Berkom wrote:
On Mon, 31 Jan 2005 12:42:33 -0800, Adrian E. Feiguin <afeiguin uci edu>
wrote:
Hi all.
This is an example, but there are many cases when I want to do
something similar:
Suppose that I change the state of a toggle button with
gtk_toggle_button_set_active or gtk_widget_set_state. The widget just
wont draw properly until I move the mouse pointer over it forcing an
expose event. What's going on? in gtk-1 I would simply call
gtk_widget_draw, but now, event calling gtk_widget_queue_draw, the
widget won't update. Can anyone explain it to me, please?
Hmm,
seems like you're hijacking the main loop somewhere, you
got a `while (42) { /* code body */ }' lying around in your code ?
If its absolutely nescisary to implement the main program loop yourself;
you can call:
`while (gtk_events_pending()) gtk_main_iteration_do (FALSE);' once
every loop.
Just a guess, OTOH maybe there is something wrong with your X server
installation (if your not recieving expose events or are unable to queue
them).
Cheers,
-Tristan
.
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