Re: [Dev-C++] Demystifying namespace
- From: Maya <EscalanteCanada netscape net>
- To: pdvz xs4all nl, gtk-list gnome org, C/C++ Programmers <prgC yahoogroups com>, Dev - C++ <dev-cpp-users lists sourceforge net>, Gtk+ mailing list <gtk-list-request gnome org>
- Subject: Re: [Dev-C++] Demystifying namespace
- Date: Thu, 18 Dec 2003 12:33:54 -0800
I want to replace the word __func__ with the word file, and you are
telling me to assign the value of __func__ to the std::string variable?
Gotta check those books again, eh!
pdvz xs4all nl wrote:
You shouldn't use #defines. #defines are cross-everything, they don't care
about scope, namespaces, functions, whatever. It's just a simple global
search&replace operation performed by the preprocessor. If you want your
namespace code to work, change it to something like:
namespace foo{
const std::string file = __func__;
const size_t line = __LINE__;
}
Note that I didn't test this though, but it should work (and didn't you mean
__FILE__ instead of __func__ there?)
Regards,
Paul
-----Original Message-----
From: dev-cpp-users-admin lists sourceforge net
[mailto:dev-cpp-users-admin lists sourceforge net] On Behalf Of Maya
Sent: Thursday, December 18, 2003 7:49 AM
To: C/C++ Programmers; Dev - C++
Subject: [Dev-C++] Demystifying namespace
I have a little bit of a problem with 'namespace'. Here is my problem:
namespace foo{
#define file __func__
#define line __LINE__
enum error_t {one, two, three};
}
namespace foo{
class loo{
public:
loo(){
std::string f = foo::file;
size_t l = foo::line;
std::cout << "file: " << f << " line: " << l << std::endl;
std::cout << foo::one << foo::two << foo::three << std::endl;
}
};
}
These std::cout's give me a parse error, what am I doing wrong?
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