[xslt] xsl:param is not works..
- From: =?ks_c_5601-1987?B?sejAur+1?= <key1020 netian com>
- To: <xslt gnome org>
- Subject: [xslt] xsl:param is not works..
- Date: Thu, 7 Jun 2001 16:40:01 +0900
Hello,
I can't English,, Sorry.. But, I try.... ^^
I have a problem..
when I use libxslt-0.9.0, xsl:param is works, using xsltproc --param tag value..
But,, libxslt-0.10.0 and 0.11.0 is not works.
xsl :
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text"/>
<xsl:param name="tag1"/>
<xsl:param name="tag2"/>
<xsl:template match="/">
<xsl:if test="$tag1">
tag1: <xsl:value-of select="$tag1"/>
</xsl:if>
<xsl:text> and </xsl:text>
<xsl:if test="$tag2">
tag2 : <xsl:value-of select="$tag2"/>
<xsl:text> !! </xsl:text>
</xsl:template>
</xsl:stylesheet>
xml:
<doc/>
xsltproc --param tag1 test1 --param tag2 test2 test.xsl test.xml
result: and !!
Help Me...
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