How to check whether the window is visible(at top/front) to user?
- From: Tao Wang <dancefire gmail com>
- To: gtkmm-list gnome org
- Subject: How to check whether the window is visible(at top/front) to user?
- Date: Fri, 30 Jul 2010 01:21:25 +1000
Hi,
I have an icon shown on tray by Gtk::StatusIcon, and I expect that if I click the icon, the main window will show, and click it again, the window will hide. So far so good. But I also expect that if the window is not visible by user, such as some other windows at the top of the window, then, when I click the tray icon, the main window will not hide (because ->get_visible() is true), instead, the window move to the front/top, so user can see it.
I use following code to do that:
if (main_window->get_visible())
{
if (main_window->is_focus())
{
main_window->hide();
}else{
main_window->raise();
}
}else{
main_window->show();
}
However, it doesn't work. is_focus() is always false when I clicked the tray icon, so the window cannot hide. Can anyone tell me where am I wrong? Thanks.
--
Regards
Tao Wang
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