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Re: [pygtk] Finding out a widget's parent
- From: David Everly <deckrider yahoo com>
- To: Christian Robottom Reis <kiko async com br>, pygtk daa com au,gtk-app-devel-list gnome org
- Subject: Re: [pygtk] Finding out a widget's parent
- Date: Wed, 8 Aug 2001 06:26:20 -0700 (PDT)
The following has worked for me:
I have a reference to a window called selectionWin, which is a
GtkFileSelection. I wanted to hide the file component, since I only
want the user to select directories. However, a scroll bar was left
behind that I didn't have a name for, so I did this:
selectionWin.__getattr__('file_list')['parent'].hide()
--- Christian Robottom Reis <kiko@async.com.br> wrote:
>
> How does one find out the widget's parent (i.e., it's immediately
> enclosing container). I've thought about writing a wrapper for
> gtk_widget->parent, but noticed there doesn't seem to be a way of
> finding
> out _what type of widget it is_ -- or is there?
>
> Is there another way of picking up it's parent? Using get_ancestor,
> perhaps?
>
> Take care,
> --
> Christian Reis, Senior Engineer, Async Open Source, Brazil.
> http://async.com.br/~kiko/ | [+55 16] 272 3330 | NMFL
>
> _______________________________________________
> pygtk mailing list pygtk@daa.com.au
> http://www.daa.com.au/mailman/listinfo/pygtk
=====
1024D/6CE00097 2001-02-24 David Everly <deckrider@yahoo.com>
Key fingerprint = E587 30C6 167F 9F25 6869 90B9 18F2 E454 6CE0 0097
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